A tube system is linear, i.e., an input
and the corresponding output
satisfy a linear equation A
=
.
Consider the following tube system:

Input x1 = 1 (units), x2 = 0
=> output y1 = 1/7 (units), y2 = 3/7, y3 = 3/7
Input x1 = 0, x2 = 1
=> output y1 = 2/5, y2 = 1/5, y3 = 2/5
What is the output corresponding to the input x1 = 2, x2 = 1?
Let
| A = 1/4 |
| 1 | 1 | 1 | 1 | ![]() | |||||||||||
| 1 | -j | -1 | j| 1 | -1 | 1 | -1 | 1 | j | -1 | -j | |
| B = 1/2 |
| 1 | 1 | ![]() | , |
| 1 | -1 |
, where
is the conjugate matrix of A, and find B-1.| F = 1/8 |
| 3 | -1 | ![]() | . | |||
| -3j | -2+3j| 1 | 1 | 3j | -2-3j | |
Find the original f.