The image R(A) of a linear mapping(a matrix) A : V -> Z is
|
:
= A
}
and the nullspace (or the kernel) N(A) is
| A
=
}.
Clearly, R(A) is a subspace of Z and N(A) is a subspace of V.
Example 1: Image, rank, nullspace and nullity
Proposition 1 The rank of a matrix A is the number of
1) linearly independent columns of A.
2) linearly independent rows of A.
Proof. 1): Let A be an m x n matrix and denote
1
2 ...
n )
Then
R(A)
<=> =
| ![]() | x1 |
| : = A![]() : | xn | |
<=> = |
| x1 |
| : = ( 1 ... n)
x1 | ![]() =
| xi i : | : | xn | xn | |
<=>
L{
1 , ...,
n }
so that R(A) = L{
1 , ...,
n }
=>
| the rank of A | = dim R(A) |
= dim L{ 1 , ..., n } | |
= the number of linearly independent vectors in { 1 , ...,
n } | |
| = the number of linearly independent columns of A | |
2) Omitted.
The proof of the following result, called the rank theorem, is also omitted:
Proposition 2 If A is an m x n matrix, then
For a linear mapping A : V -> Z, where V = n and dim Z = m, we have
It follows from the previous proposition, that if A : V -> Z, dim V = n, then dim R(A) = n - dim N(A) => A cannot increase the dimension of V.
Proposition 3. If A and B are matrices, then
min{the rank of A, the rank of B}The elementary row operations do not affect the rank of a matrix A.